C code which will convet a decimal number to Roman number
-----------------------------------------------------------------------
#include stdio.h
#include conio.h
main()
{
int a,b,c,d,e;
char x;
ss:
clrscr();
printf("---------------------------------\n");
printf("DECIMAL TO ROMAN\n");
printf("----------------------------------\n");
printf("PRESS 'C' to CONTINUE or'X' to EXIT");
scanf("%c",x);
switch (x)
{
case 'C':
goto cc;
case 'X':
goto xx;
default:
goto ss;
}
cc:
printf("ENTER NUMBER (between 1-3000):");
scanf("%d",&e);
while (e==0||e>3000 )
{
printf("ERROR: Invalid Input!");
printf("Enter the number again:");
scanf("%d",&e);
}
if (e>3000)
printf("Invalid");
a = (e/1000)*1000;
b = ((e/100)%10)*100;
c = ((e/10)%10)*10;
d = ((e/1)%10)*1;
if (a ==1000)
printf("M");
else if (a ==2000)
printf("MM");
else if (a ==3000)
printf("MMM");
if (b == 100)
printf("C");
else if (b == 200)
printf("CC");
else if (b == 300)
printf("CCC");
else if (b == 400)
printf("CD");
else if (b ==500)
printf("D");
else if (b == 600)
printf("DC");
else if (b == 700)
printf("DCC");
else if (b ==800)
printf("DCCC");
else if (b == 900)
printf("CM");
if (c == 10)
printf("X");
else if (c == 20)
printf("XX");
else if (c == 30)
printf("XXX");
else if (c == 40)
printf("XL");
else if (c ==50)
printf("L");
else if (c == 60)
printf("LX");
else if (c == 70)
printf("LXX");
else if (c ==80)
printf("LXXX");
else if (c == 90)
printf("XC");
if (d == 1)
printf("I");
else if (d == 2)
printf("II");
else if (d == 3)
printf("III");
else if (d == 4)
printf("IV");
else if (d ==5)
printf("V");
else if (d == 6)
printf("VI");
else if (d == 7)
printf("VII");
else if (d ==8)
printf("VIII");
else if (d == 9)
printf("IX");
getch();
xx:
return 0;
}
No comments:
Post a Comment